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Bug on the code-example site

hey everybody

i found a bug on the documentation site... i was looking for a code-example for PHP and found this very useful site: http://developer.yahoo.com/yql/guide/yql-c...es.html#yql_php

but actually there is a bug in the code (at least it wouldn't work on my server). the first line of this code-snippet is wrong:

CODEBOX
curl_init($yql_query_url);  
curl_setopt($session, CURLOPT_RETURNTRANSFER,true);
$json = curl_exec($session);

the right structure would be as following (the declaration of the variable $session is missing):
CODEBOX
$session = curl_init($yql_query_url);  
curl_setopt($session, CURLOPT_RETURNTRANSFER,true);
$json = curl_exec($session);


it would be nice, if somebody would correct that error... i was trying to get the code to work for a long time, until i figured it out. so please correct this :-)

thanks

by
1 Reply
  • Thanks for catching and reporting this -- we'll get that fixed shortly.

    Brian Cantoni
    Yahoo! Developer Network
    0
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