Can you post your full YQL execute block here?

Are you using y.rest?

Thanks -Paul YQL Team

Hi Paul,

Thanks for replying. I'm a newbie to YQL. I tried this referring to the examples in the YQL documentation. I'm not sure where I'm going wrong. Please help me.

<?xml version="1.0" encoding="UTF-8"?>
<table xmlns="http://query.yahooapis.com/v1/schema/table.xsd">
    <meta>
        <author>Karthik Vasudevan</author>
        <documentationURL>http://www.kaartz.in/htmle/docu/index.php</documentationURL>
        <sampleQuery>select * from {table} where url="http://ca.music.yahoo.com/" and xpath="where url="//*[@class='txt']//*[@class='accd']/span[1]"</sampleQuery>
    </meta>
    <bindings>
        <select itemPath="query.results" produces="XML">
            <urls>
                <url></url>
            </urls>
            <inputs>
                <key id="urle" type="xs:string" paramType="variable" />
                <key id="xpath1" type="xs:string" paramType="variable" />
            </inputs>
                    <execute><![CDATA[
                          var query = null;
                          query = y.query("http://query.yahooapis.com/v1/public/yql?q=select * from html where url=@urle and xpath=\"" xpath1 "\"", {urle:urle, xpath1:xpath1});
                          response.object = query.results;
                          ]]></execute>
        </select>
    </bindings>
</table>

this wrong

y.query("http://query.yahooapis.com/v1/public/yql?q=select * from html where url=@urle and xpath=\"" xpath1 "\"", {urle:urle, xpath1:xpath1})

do something like this

var output=y.query("show tables", param);
response.object = output.results; 

Thanks Markandey.

I would really appreciate, if you could explain how to do it correctly. I'm pretty new to YQL.